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Day_5_Build_AI_Agent.py
from groq import Groq
from agents import AIAgent

client = Groq()

# Initialize autonomous agent
agent = AIAgent(
    model="llama3-70b-versatile",
    tools=[search_web, read_url_content],
    memory_enabled=True
)

print("Agent active...")
agent.run("Find early-career developer roles in Bangalore")
> python Day_5_Build_AI_Agent.py
[Agent] Agent active...
[Agent] Searching web for 'early-career developer roles Bangalore'...
[Agent] Found 15 matching job listings.
[Agent] Filtering by skills: Python, SQL, REST APIs...
[Agent] Analysis complete. 3 high-match roles identified.
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E

Software Engineer - Intermediate

Equifax
New
📍 Trivandrum, Kerala, India 💼 Job 💰 ₹15LPA - ₹25LPA 🎓 Experience Batch
Java Spring Boot Cloud technology
View Details & Apply
Q

AI/ML Engineer

Quest Global
New
📍 Thiruvananthapuram, Kerala, India 💼 Job 💰 ₹18LPA - ₹30LPA 🎓 Experience Batch
Python TensorFlow PyTorch C++/Java
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A

Front-end Developer

AquarLabs
New
📍 Visakhapatnam Rural mandal, India (Remote) 💼 Job 💰 ₹4LPA - ₹7LPA 🎓 2025, 2026 Batch
HTML CSS JavaScript React.js
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Rohi AI Tutor

How do I fetch the Swiggy restaurant menu using requests in Python?

To call Swiggy's API, you need to simulate a real browser request by passing a User-Agent header. Otherwise, Swiggy's API blocks standard Python requests with a 403 Forbidden error.

Here is how you do it using the requests library:

import requests

headers = {
    'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64)'
}
url = 'https://www.swiggy.com/dapi/menu/pl?page-type=REGULAR_MENU&lat=12.9716&lng=77.5946&restaurantId=12345'

response = requests.get(url, headers=headers)
menu_data = response.json()
print("Success! Parsed menu json.")

Give that a try! If you still get blocked, let me know.

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How to Learn Python for Free in India — 100 Day Complete Roadmap

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